Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

398
Visualizações
Is there any difference between "mutating" function and "inout" parameters in Swift?

As per Swift documentation both mutating and inout keywords are used to modify the value types from within a function. Is there any difference between "mutating" and "inout" and any special case where we need to use either of them.

over 4 years ago · Santiago Trujillo
3 Respostas
Responde à pergunta

0

mutating marks a method. inout marks a parameter. They are completely different things.

Methods marked with mutating can mutate self i.e. set properties of self, reassign self etc.

struct Foo {
    var foo: Int

    mutating func mutate() {
        foo += 1 // this is mutating self
    }
}

Parameters marked with inout basically become var variables, as opposed to let constants. You can change them, and the changes will also reflect on the caller's side.

func f(_ x: inout Int) {
    x = 10
}

var a = 1
f(&a)
print(a) // 10
over 4 years ago · Santiago Trujillo Relatório

0

For me I see difference just in places where they are used.

Parameter marked with inout keyword allows you to pass your value to any method similary as reference

func square(inout num: Int) { 
    num = num * num
}

In contrast to it, method marked with mutating keyword is used in type scope and allows you to change value itself from this method

extension Int {

    mutating func square() {
        self = self * self
    }

}
over 4 years ago · Santiago Trujillo Relatório

0

Value types' instance methods cannot change the value type's properties (or value itself), unless they are marked as mutating.

Functions of any kind cannot change their parameters (and have the change propagate outside the function) unless those parameters are marked as inout.

They do a similar job, but in different contexts.

over 4 years ago · Santiago Trujillo Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda